The Final BAM thread before Sunday!!!
08-05-2009 | 02:33 AM
#52
Registered User
iTrader: (3)
Joined: Mar 2008
Posts: 6,967
From: Upper North Bay
Car Info: '15 LE STI, '06 WRX White Wheeled Wagon, '06 B9
if everyone on the list for caravans goes there is 131 cars caravaning to BAM not including the people in the sac area cuz they didnt make a list of people
that is just ****ign crazy
everyone be good cuz that will be like shooting fish in a barrel for CHP
that is just ****ign crazy
everyone be good cuz that will be like shooting fish in a barrel for CHP
08-05-2009 | 09:56 AM
#53
Churro Aficionado
iTrader: (38)
Joined: Feb 2008
Posts: 54,642
From: IG - @thomas.teammoist
Car Info: IG - @TEAMMOISTOFFICIAL
im guessing 7-10 from Sac caravan but I could be way off...
not everyone will caravan tho so a lot of ppl will still show up.....its going to be good
not everyone will caravan tho so a lot of ppl will still show up.....its going to be good
08-07-2009 | 10:10 PM
#54
VIP Member
Joined: Dec 2002
Posts: 3,548
From: N38.6775* W120.0805*
Car Info: psm.03.wrx.wgn
08-08-2009 | 01:00 AM
#58
1) A double acting cylinder with a 2.5" bore and a .5" rod extends through a 20" stroke while producing a 300 lb force, and retracts through the same stroke with a 500 lb force. If the extension time is 4 seconds and the retraction time is 5 seconds how much SCFM is required to power the cylinder?
Velocity=Distance/Time(5)
20 in/4 sec(5)= 25ft/min
Area=.7854(d^2)
.7854(2.5^2)=4.9 in^2
CFM=Area*Velocity/144
4.9 * 25/144 = .85 CFM
Force=Pressure*Area
300lbs/4.9=P*4.9/4.9 P=61.22 PSI
Compression Ratio (CR) = Pressure + 14.7/14.7
61.22 psi + 14.7/14.7 = 5.16
SCFM = CR * CFM
5.16 * .85 = 4.386 SCFM for the extension side
Repeat for retraction side - the rod
Answer is 9.707 SCFM
bump
08-08-2009 | 01:04 AM
#59
Registered User
iTrader: (3)
Joined: Mar 2008
Posts: 6,967
From: Upper North Bay
Car Info: '15 LE STI, '06 WRX White Wheeled Wagon, '06 B9
In case you guys were wondering here is the answer.
Velocity=Distance/Time(5)
20 in/4 sec(5)= 25ft/min
Area=.7854(d^2)
.7854(2.5^2)=4.9 in^2
CFM=Area*Velocity/144
4.9 * 25/144 = .85 CFM
Force=Pressure*Area
300lbs/4.9=P*4.9/4.9 P=61.22 PSI
Compression Ratio (CR) = Pressure + 14.7/14.7
61.22 psi + 14.7/14.7 = 5.16
SCFM = CR * CFM
5.16 * .85 = 4.386 SCFM for the extension side
Repeat for retraction side - the rod
Answer is 9.707 SCFM
bump
Velocity=Distance/Time(5)
20 in/4 sec(5)= 25ft/min
Area=.7854(d^2)
.7854(2.5^2)=4.9 in^2
CFM=Area*Velocity/144
4.9 * 25/144 = .85 CFM
Force=Pressure*Area
300lbs/4.9=P*4.9/4.9 P=61.22 PSI
Compression Ratio (CR) = Pressure + 14.7/14.7
61.22 psi + 14.7/14.7 = 5.16
SCFM = CR * CFM
5.16 * .85 = 4.386 SCFM for the extension side
Repeat for retraction side - the rod
Answer is 9.707 SCFM
bump
although i did lol at the kilojarbles comment
08-08-2009 | 01:04 AM
#60
In case you guys were wondering here is the answer.
Velocity=Distance/Time(5)
20 in/4 sec(5)= 25ft/min
Area=.7854(d^2)
.7854(2.5^2)=4.9 in^2
CFM=Area*Velocity/144
4.9 * 25/144 = .85 CFM
Force=Pressure*Area
300lbs/4.9=P*4.9/4.9 P=61.22 PSI
Compression Ratio (CR) = Pressure + 14.7/14.7
61.22 psi + 14.7/14.7 = 5.16
SCFM = CR * CFM
5.16 * .85 = 4.386 SCFM for the extension side
Repeat for retraction side - the rod
Answer is 9.707 SCFM
bump
Velocity=Distance/Time(5)
20 in/4 sec(5)= 25ft/min
Area=.7854(d^2)
.7854(2.5^2)=4.9 in^2
CFM=Area*Velocity/144
4.9 * 25/144 = .85 CFM
Force=Pressure*Area
300lbs/4.9=P*4.9/4.9 P=61.22 PSI
Compression Ratio (CR) = Pressure + 14.7/14.7
61.22 psi + 14.7/14.7 = 5.16
SCFM = CR * CFM
5.16 * .85 = 4.386 SCFM for the extension side
Repeat for retraction side - the rod
Answer is 9.707 SCFM
bump
