The Final BAM thread before Sunday!!!
08-05-2009, 01:33 AM
#52
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Join Date: Mar 2008
Location: Upper North Bay
Posts: 6,967
Car Info: '15 LE STI, '06 WRX White Wheeled Wagon, '06 B9
if everyone on the list for caravans goes there is 131 cars caravaning to BAM not including the people in the sac area cuz they didnt make a list of people
that is just ****ign crazy
everyone be good cuz that will be like shooting fish in a barrel for CHP
that is just ****ign crazy
everyone be good cuz that will be like shooting fish in a barrel for CHP
08-07-2009, 09:10 PM
#54
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Join Date: Dec 2002
Location: N38.6775* W120.0805*
Posts: 3,548
Car Info: psm.03.wrx.wgn
08-08-2009, 12:00 AM
#58
1) A double acting cylinder with a 2.5" bore and a .5" rod extends through a 20" stroke while producing a 300 lb force, and retracts through the same stroke with a 500 lb force. If the extension time is 4 seconds and the retraction time is 5 seconds how much SCFM is required to power the cylinder?
Velocity=Distance/Time(5)
20 in/4 sec(5)= 25ft/min
Area=.7854(d^2)
.7854(2.5^2)=4.9 in^2
CFM=Area*Velocity/144
4.9 * 25/144 = .85 CFM
Force=Pressure*Area
300lbs/4.9=P*4.9/4.9 P=61.22 PSI
Compression Ratio (CR) = Pressure + 14.7/14.7
61.22 psi + 14.7/14.7 = 5.16
SCFM = CR * CFM
5.16 * .85 = 4.386 SCFM for the extension side
Repeat for retraction side - the rod
Answer is 9.707 SCFM
bump
08-08-2009, 12:04 AM
#59
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iTrader: (3)
Join Date: Mar 2008
Location: Upper North Bay
Posts: 6,967
Car Info: '15 LE STI, '06 WRX White Wheeled Wagon, '06 B9
In case you guys were wondering here is the answer.
Velocity=Distance/Time(5)
20 in/4 sec(5)= 25ft/min
Area=.7854(d^2)
.7854(2.5^2)=4.9 in^2
CFM=Area*Velocity/144
4.9 * 25/144 = .85 CFM
Force=Pressure*Area
300lbs/4.9=P*4.9/4.9 P=61.22 PSI
Compression Ratio (CR) = Pressure + 14.7/14.7
61.22 psi + 14.7/14.7 = 5.16
SCFM = CR * CFM
5.16 * .85 = 4.386 SCFM for the extension side
Repeat for retraction side - the rod
Answer is 9.707 SCFM
bump
Velocity=Distance/Time(5)
20 in/4 sec(5)= 25ft/min
Area=.7854(d^2)
.7854(2.5^2)=4.9 in^2
CFM=Area*Velocity/144
4.9 * 25/144 = .85 CFM
Force=Pressure*Area
300lbs/4.9=P*4.9/4.9 P=61.22 PSI
Compression Ratio (CR) = Pressure + 14.7/14.7
61.22 psi + 14.7/14.7 = 5.16
SCFM = CR * CFM
5.16 * .85 = 4.386 SCFM for the extension side
Repeat for retraction side - the rod
Answer is 9.707 SCFM
bump
although i did lol at the kilojarbles comment
08-08-2009, 12:04 AM
#60
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Join Date: Apr 2008
Location: Bay Area
Posts: 2,099
Car Info: RWD Camry
In case you guys were wondering here is the answer.
Velocity=Distance/Time(5)
20 in/4 sec(5)= 25ft/min
Area=.7854(d^2)
.7854(2.5^2)=4.9 in^2
CFM=Area*Velocity/144
4.9 * 25/144 = .85 CFM
Force=Pressure*Area
300lbs/4.9=P*4.9/4.9 P=61.22 PSI
Compression Ratio (CR) = Pressure + 14.7/14.7
61.22 psi + 14.7/14.7 = 5.16
SCFM = CR * CFM
5.16 * .85 = 4.386 SCFM for the extension side
Repeat for retraction side - the rod
Answer is 9.707 SCFM
bump
Velocity=Distance/Time(5)
20 in/4 sec(5)= 25ft/min
Area=.7854(d^2)
.7854(2.5^2)=4.9 in^2
CFM=Area*Velocity/144
4.9 * 25/144 = .85 CFM
Force=Pressure*Area
300lbs/4.9=P*4.9/4.9 P=61.22 PSI
Compression Ratio (CR) = Pressure + 14.7/14.7
61.22 psi + 14.7/14.7 = 5.16
SCFM = CR * CFM
5.16 * .85 = 4.386 SCFM for the extension side
Repeat for retraction side - the rod
Answer is 9.707 SCFM
bump
